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Case Study Comparison on Psychrometric Chart

How to use the Psychrometric Chart:

LINES AND SCALES

Dry Bulb Temperature Scale
Humidity Ratio Scale
DewPoint Scale
Enthalpy Scale
Sensible Heat Ratio Index
Sensible Heat Ratio Index Origin
Vapor Pressure Scale
Dry Bulb Temperature Line
Wet Bulb Temperature Line
Humidity Ratio Line
Relative Humidity Line
Specific Volume Line
A - Humidification
B - Heat and Humidity
C - Heating
D - Solid Desiccant
E - Liquid Desiccant
F - Cooling Coil
G - Evaporative Cooling

Commonly Used Sea Level Rules of Thumb:

Qtotal = CFM x (hi-hf) x 4.5 Btuh
Qsensible = CFM x (ti-tf) x 1.085 Btuh
Qlatent = CFM x (Gri - Grf) x .68 Btuh
Humidification = CFM x (Grf - Gri) / 1,555 lbs/hr

PROBLEM 1

Outside Air (OA) of 3000 cfm at Boston summer cooling conditions of 90°F dry bulb and 73°F wet bulb is to be conditioned to room neutral 73°F and 45% relative humidity. Using the psychrometric chart, estimate the total energy required for a traditional cooling coil and re-heat coil.


Solution

Locate the Outside Air and Leaving Air points and record the OA specific volume and LA humidity ratio and enthalpy for both points.
      OA Specific Volume = 14.156 cu.ft./lba
      OA Enthalpy = 36.642 Btu/lb
      LA Enthalpy = 26.034 Btu/lb
      LA Humidity Ratio = 54.5 gr/lb

Locate the point (CC) where the LA humidity ratio line intersects the saturation curve and record the Enthalpy.
      CC Enthalpy = 20.548 Btu/lb

The cooling coil energy for dehumidification can be estimated by the following equation:
      Q = (hOA - hCC) x (cfm x 60) / spec.vol.OA
      Q = (36.6 - 20.5) x (3000 x 60) / 14.156
      Q = 204,718 Btu/hr

The heating coil energy for air re-heating to the desired dry bulb temperature can be estimated by the following equation:
      Q = (hLA - hCC) x (cfm x 60) / spec.vol.OA
      Q = (26.0 - 20.5) x (3000 x 60) / 14.156
      Q = 69,935 Btu/hr

Estimated Total Energy
Q = 204,718 Btu/hr + 69,935 Btu/hr

Estimated Total Energy
Q = 274,653 Btu/hr